Page 73 - The Basics IA by ETron Circuit Labs

Procedure:Assemble the circuit and connect a 9-volt battery to the Battery Snap and observe that the LED is lit. Now, remove one resistor from the circuit board. What happened to the LED? Did it get dimmer or brighter?Observations:By doing this experiment, you have seen that the LED gets dimmer as you remove resistors in parallel. Each resistor you add in parallel reduces the total resistance of the circuit. Therefore the more resistors you have in parallel the brighter the LED.Ohm’s Law as applied to resistors in parallel:Formula to find the total resistance: 1/R total = ( 1/R1 + 1/R2 + 1/R3)1/R total = (1/1000 + 1/1000 + 1/1000) 1/R total = 3/10003/R total = 1000R total = 333 ohms Using Ohm’s Law: ExampleE=IxR9 = I x 333I = 9/333 or approximately 0.027 amps or 27 mAR1R2R3hole 4hhole 17hRESISTORhole 4ghole 17g1K $ (Brown, Black, Red, Gold) 1K $ (Brown, Black, Red, Gold) hole 4jhole 17j1K $ (Brown, Black, Red, Gold) Anode CathodeLIGHT EMITTING DIODE (LED)LED 1Cathode (flat side)B1hole 21j hole 22jREDBLACKred = hole 25e black = hole 22f0 MAHere’s What You’ll Need...SCAN HERE TO SEE MORE ONLINE71AnodeLAB 36Visit us online at www.ETronCircuit.com for more exciting projectsLab Observations